Two blocks A and B of masses mA = 1 kg and mB = 3 kg are kept on the table as shown in figure. The coefficient of friction between A and B is 0.2 and between B and the surface of the table is also 0.2. The maximum force F that can be applied on B horizontal, so that the block A does not slide over the block B is:
[Take g = 10 m/s²] (A) 8 N (B) 16 N
(C) 12 N (D) 40 N
Attachments:
Answers
Answered by
2
Answer:
B. will be correct answers
Explanation:
hope the answer will help you
Attachments:
Similar questions