two blocks M and n of mass 8 kg and 4kg are arranged as shown in the figure and they are kept on a smooth horizontal surface a horizontal force of 6 newton is applied on the first block due to which the move with constant acceleration calculate the force between the blocks
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Answer:a=1/2,T=2
Explanation:very easy first the equation 1 is 6N‐T=8a and equation 2 is T=4a
Then we get a=1/2 and put value of a in any equation
(a=acceleration)
(T=tension)
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