Question

Two blocks of 100N (A) and 50N (B) are connected by a flexible but
inextensible string as shown in figure. Assuming coefficient of friction
between block 100N and horizontal surface is 0.25, Find the acceleration of
masses and tension in the string.
AP
15
1
B​

Answer 1

Answer:

l don't know? the answer

Answer 2

Given info : Two blocks of 100N (A) and 50N (B) are connected by a flexible but inextensible string as shown in figure. Assuming coefficient of friction between block 100N and horizontal surface is 0.25.

To find : the acceleration of masses and tension in the string are ...

solution : draw free body diagram,

let acceleration of the masses is a and tension in the string is T.

for block A,

T - fr = Ma

⇒T - μMg = Ma

⇒T - 0.25 × 100 N = 10kg × a [ assuming g = 10 m/s² ]

⇒T - 25 = 10a ...(1)

for block B

mg - T = ma

⇒50N - T = 5kg × a

⇒50 - T = 5a ...(2)

from equations (1) and (2) we get,

25 = 15a

⇒a = 5/3 m/s²

and T = 10 × 5/3 + 25 = 50/3 + 25 = 125/3 N

Therefore the acceleration of masses and tension in the string are 5/3 m/s² and 125/3 N respectively.