Two blocks of cheese have approximately the same mass.one measures 7cm x 6cm x 12 and the other measures 8cm x 8cm x 8cm. Which block will need more shrink wrap? Explain.
Answers
Answer:
2nd vala
Step-by-step explanation:
tsa of first
2( 7*6+6*12+12*7)
2(42 + 72+84)=2(198)=396
tsa of second
2(8*8+8*8+8*8)= 2(64+64+64)= 2(192)=384
Answer:Solution:
First cheese block measurements => 7 cm x 6 cm x 12 cm
Second cheese block measurements => 8 cm x 8 cm x 8 cm
Cheese block is in a shape of cuboid.
Surface area of cuboid = 2(LW + LH + WH)
where,
L = Length
W = Width
H = Height
Surface area of first cheese block = 2(LW + LH + WH)
= 2(7*6 + 7*12 + 6*12)
= 2(42 + 84 + 72)
= 2 * 198
= 396 cm²
Surface area of second cheese block = 2(LW + LH + WH)
= 2(8*8 + 8*8 + 8*8)
= 2(64 + 64 + 64)
= 2 * 192
= 384 cm²
The first cheese block will require more shrink wrap as it is having more surface area so, required shrink wrap to cover will be more too.
Shrink wrap is that thing which is used to cover things and is made up of polymer plastic film.
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