two blocks of lead, one twice as heavy as the other, are at 50°C. the ratio of the hear content of the heavier block to that of the lighter block is?
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Q = mSdT
Both are made up of lead hence S is constant. Temperature given is constant.
Therefore,
Q ∝ m
Ratio of heat content = Ratio of their masses = 2 : 1
Both are made up of lead hence S is constant. Temperature given is constant.
Therefore,
Q ∝ m
Ratio of heat content = Ratio of their masses = 2 : 1
sanketprasad:
thank you very much!!
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