Two blocks of mass 4kg and 2kg are placed side by side on a smooth
horizontal surface as shown in the figure. A horizontal force of 20 N is
applied on 4 kg block. The acceleration of each block
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ANSWER
The free body diagram of both the blocks are as shown in the figure.
a=
4+2
F
=
4+2
20
=
3
10
Using ΣF
x
=ma
x
For 4kg block, 20−N=4a=4×
3
10
N=20−
3
40
=
3
20
N
This can also be solved as below
For 2kg block, N=2a=2×
3
10
=
3
20
N
Here, N is normal reaction between the two blocks.
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