Question

Two blocks of mass m, and m2 are placed on a smooth
horizontal surface as shown in figure. When a horizontal force
Fis applied on my then magnitude of normal reaction between
m; and m2 is
m
F-
m2

Answer 1

Answer:

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11th

Physics

Laws of Motion

Solving Problems In Mechanics

Two blocks of masses m1 and...

PHYSICS

Two blocks of masses m

1

and m

2

are placed side by side on a smooth horizontal surface as shown in Fig.6.31. A horizontal force F is applied on the block.

a. Find the acceleration of each block.

b. Find the normal reaction between the two blocks.

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ANSWER

Method 1 :

Since the two blocks always remain in contact with each other, they must move with the same acceleration. Using Newton's second law, we get

For block m

1

:F−N=m

1

a......(i)

For block m

2

:N=m

2

a......(ii)

On adding the two equations, we get

F=(m

1

+m

2

)a⇒a=

m

1

+m

2

F

Substituting the value of a in (ii), we get N=m

2

a=

m

1

+m

2

Fm

2

Method 2 :

The situation may be considered as follows: Instead of drawing the free-body diagrams of each block, we can draw the free-body diagram of both blocks together as shown in Fig.6.33.

The net force acting on the system is F, and the total mass of the system is

m

1

+m

2

. Thus, a=

m

1

+m

2

F

To find out the normal reaction N between the two blocks, we can imagine the following; Block m

2

is moving with an acceleration a; therefore, the net force acting on it must be m

2

a, which is nothing but the normal reaction applied by the block m

1

. Thus,

N=m

2

a=

m

1

+m

2

m

2

F

solution

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