Question

Two blocks of mass m1 = 20kg and m2 =12kg are connected by a metal rod of mass 8 kg. The system is pulled vertically up by applying a force of 480 n as shown. The tension at the mid - point of the rod is

Answer 1

192 N is the tension at the mid-point of the rod.

Explanation:

Given,

Mass of first block or $m_{1}$ = 20kg

Mass of the second block or $m_{2}$ = 12 kg

Mass of the metal rod = 8kg

∵ Total mass = 20kg + 12kg + 8kg

= 40kg

Total force applied = 480N       (given)

g(gravitational force) = 10m/s^2

As we know,

ma = F − mg

40a = 480 − 40×10

a = (480 - 400)/40

a = 80/40

a = 2m/s

Now,

At the rod's mid-point, the total mass of the rod

= 12 + 4

= 16kg                    (since half and $m_{2}$ are below)

To find the tension at the mid-point,

T(Tension) = m(g+a)

= 16(10+2)

= 192N

Therefore, 192 N is the tension at the mid-point.

Learn more: force

brainly.in/question/19654957