Question

two blocks of masses 2 kg and 1 kg are in contact with each other on horizontal frictionless table. When a horizontal force of 3 N is applied to the block of mass 2 kg, the value of force of contact between the two block is:
a) 4N
b) 3N
c) 2N
d) 1N​

Answer 1

The acceleration of the system is, a = 3/(2 + 1) = (3/3)=1 m/s2

The reaction force experienced by the blocks is equal to the force on 1 kg that makes it move with acceleration ‘a’ which is = 1 × 1 = 1 N

hope it helps