Question

Two blocks of masses 2 kg and 5 kg are connected by an ideal string passing over a pulley the block of mass 2 kg is forced to slide on the surface inclined at an angle of 30 degree with the horizontal where does the block of 5 kg mass hangs freely find the acceleration of the system and the tension in the string given you is equal to 0.30

Answer 1

The acceleration of the system is a = 5 m/s^2

Explanation:

We are given that:

• Mass m1 = 2 Kg

• Mass m2 = 5 Kg
• Angle "θ" = 30°
• Tension in the string "T" = 0.30 N

Solution:

T - mgsinθ - u mgcosθ = 2 a ----(1)

50 g - T = 5 a    --------(2)

5 g - 8 g x 1/2 - 0.3 x 2 g x √3 / 2 = = 7 a

a = 4 g - 0.3 x √3 g / 7

a = 40 - 3 (1.73) / / 7

a = 40 - 5.1 g / 7

a = 5 m/s^2

Thus the acceleration of the system is a = 5 m/s^2