Two blocks of masses '3m' and '2m' are in contact ona smooth table. A force P is first
applied horizontally on block of mass 3m' and then on mass '2m'. The contact forces
between the two blocks in the two cases are in the ratio.
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Explanation:
f
1
=(2m)(acc.)
=2m×
5m
P
=
5
2
P
f
2
=(3m)(acc.)
=3m×
5m
P
=
5
3
P
f
2
f
1
=
3P/5
2P/5
=
3
2
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