Question

Two blocks of masses 5 kg and 10 kg are connected by massless spring. A force of 10 N acts on 10 kg mass. At the instant 5 kg mass has an acceleration of 0.2 m/s, the acceleration of 10 kg mass would be

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Answer 1

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Answer 2

Answer:

The acceleration of the block $2$ of mass $10kg$ measured is $0.9m/s^{2}$.

Explanation:

Given,

The mass of the block $1$, m₁ = $5kg$

The mass of the block $2$, m₂ = $10kg$

The acceleration of the block $1$, a₁ = $0.2m/s$

The force on the block $2$, F₂ = $10N$

The acceleration of the block $2$, a₂ =?

As we know,

• Force = mass × acceleration

Thus, for block $1$,

• $F_{1} = m_{1}\times a_{1}$
• $F_{1} = 5\times 0.2$ = $1N$

Now, on block $2$,

• Net force = $F_{2} - F_{1}$
• F = $10 - 1$ = $9N$

Therefore,

• a₂ = $\frac{F}{m_{2} }$ = $\frac{9}{10}$ = $0.9m/s^{2}$.

Hence, the acceleration of the block $2$ of mass $10kg$, a₂ = $0.9m/s^{2}$.