Question

Two blocks of masses 8 kg and 2 kg respectively lie on a smooth horizontal surface in contact with one other.They are pushed by a horizontal applied force of 15N .calculate the force exerted on the 2 kg masses

Answer 1

Solution:

m1 = 8 kg

m2 = 2 kg

total mass of the system = m = 2+8 = 10 kg

net force on the system = F = 15 N

net acceleration of the system = a = F/m

=> a = 15/10 = 1.5 m/s^2

acceleration of m2 = a = 1.5 m/s^2

net force on m2 = 2 × 1.5 = 3 N ..... answer..

Answer 2

Answer:

3N

Explanation:

M1 = 8kg

M2 = 2kg

Total force applied = 15N

F21 = ?

F = ma

15 = (8+2)×a

15 = 10×a

a = 15/10

a = 3/2

a = 1.5

F21 = ma

F21 = 2× 1.5

F21 = 3N