Two blocks of masses m1=2 kg and m2=4 kg are released from rest find acceleration of centre of mass
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The net force on the pulley mass system
F= m1 g-m2g
= 4g-2g = 2g
= 2×10 = 20 N
Acceleration of the centre of mass
a = F/ m1+m2
= 20/4+2
=10/3 m/s²
Distance traveled in 9 seconds
s = 1/2at²
= 1/2×10/3×9²
= 135m
Thus speed of centre of mass after 9 sec,
v = at = 10/3×9
= 30m/s
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