Question

Two boatmen start simultaneously from the opposite shore of a river and they cross each
other after 45 minutes of their starting from the respective shores. They rowed till they
reached the opposite shore and returned immediately after, reaching the shores. When will
they cross each other again?​

Answer 1

Answer:

After reaching the shore they will meet again after 90 min of their first meet .

Step-by-step explanation:

Given as :

Time taken by both boatmen that start from opposite shore of river = 45 min

Let The total distance between two shore AB = = d km

One boatman move from point A

Another boatman move from point B

ie. After 45 min, both boatman complete $\dfrac{d}{2}$ km distance .

So, rest of $\dfrac{d}{2}$ km is completed in another 45 min ,

So, After first meet and travelling another 45 min ,both will reach opposite shore .

Now, Once again they start from Point A and point B

So, After traveling $\dfrac{d}{2}$ km they meet once again

and with same speed they take 45 min again to cover $\dfrac{d}{2}$ distance

So, Total time after first meet = 45 min + 45 min = 90 min

Hence, After reaching the shore they will meet again after 90 min of their first meet . Answer

Answer 2

Step-by-step explanation:

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