Two bodies a and b have their masses 1:3and kinetic energy is 1:3 The velocity ratio is
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e=12mv2e=12mv2
Hence
e1e2=m1v1m2v2=m1m2(v1v2)2e1e2=m1v1m2v2=m1m2(v1v2)2
Substitue with the given data
13=313=3 (v1v2)2or(v1v2)2or
v1v2=13v1v2=13 negative solution is not acceptable.
Hence
e1e2=m1v1m2v2=m1m2(v1v2)2e1e2=m1v1m2v2=m1m2(v1v2)2
Substitue with the given data
13=313=3 (v1v2)2or(v1v2)2or
v1v2=13v1v2=13 negative solution is not acceptable.
Answered by
1
Given,
M : m = 1 : 3 -> 1
1/2MV² : 1/2mv² = 1 : 3 - >2
Putting eq. 1 into 2,
V² : v² = 1 : 1
=>V : v = 1 : 1.
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M : m = 1 : 3 -> 1
1/2MV² : 1/2mv² = 1 : 3 - >2
Putting eq. 1 into 2,
V² : v² = 1 : 1
=>V : v = 1 : 1.
Hope this will help you.
If you like my answer
Please mark it as brainliest
And
Be my follower if possible.
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