Question

Two bodies A and B having masses2kg and 4kg are separated by 2m where should a body of mass 1kg be placed so that gravitational force on this body due to bodies of A and B is zero

Answer 1

hey there !!

2kg●-------------•-------------------● 4kg
•|<------x-----|-----(2-x)------->|

=) Let 1 kg mass be placed at 'x' distance from mass 2kg

◆Force between 2kg and 1kg :-

=) F21 = G ×2×1/x^2 = 2G/x^2 -----(1)

◆Force between 4kg and 1 kg :-

=) F41 = G×4×1/(2-x)^2 = 4G/(2-x)^2 --(2)

now from Newton's 3rd law :

=) F21 = F41

=) 2G/x^2 = 4G/(2-x)^2

=) 2x^2 = (2-x)^2

=) √2 x = (2 - x)

=) √2x = 2 - x

=) (√2 +1)x = 2

=) x = 2/(√2+1) m

______________________________

Hope it will help u ^_^

Answer 2

Answer:

The right answer is 0.83

Explanation:

hope it helps