two bodies A and B of mass of 150g and 250g respectively are approaching each other.Both particles have a speed of 3m/s.Find the magnitude of the total linear momentum of the system of the two particles.
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P= mv
M1 = 150g
M2 = 250g
Speed= 3m/s
So
P1 = 150*3 =450
P2= 250*3= 750
Total p
450+ 750 = 1200..
M1 = 150g
M2 = 250g
Speed= 3m/s
So
P1 = 150*3 =450
P2= 250*3= 750
Total p
450+ 750 = 1200..
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