Two bodies A and B of masses 100 g and 200 g respectively are dropped near the earth's surface. Let the accelerations of A and B be a1, and a2 respectively.
(a)a1=a2 (b)a1<a2 (c) a1>a2
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Answer:
Explanation:
f the question has asked to find the time when they reach the bottom then it will be same for both A and B .
as we know H = 0t + 1/2 gt^2 or t = (2H/g)^2
● Only the impulse of heavier body will be more .
Their acceleratn has to be Same .
if Suppose they are a1 and a2 . Then it may be due to air friction and also air is different in the places where A and B are dropped.
● Therefore in that case consider net acceleration to be a1 and a2 .
a1 = g - (accln due to air friction in atmosphere1)
a2 = g - (accln due to air friction in atmosphere 2)
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samriddhachandra14:
you have just copied.. I have already seen that ans before
I wanted u to and the option and explain
Answered by
1
Answer:
non of these non of these
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