Question

Two bodies A and B start from rest from the same point with a uniform acceleration of 2 meter per second square.If B starts one second later then the two bodies are seperated at the end of the next second by

Answer 1

B starts 1sec later than A.

So, at the end of next sec total travel time of A & B will be 2 sec & 1 sec respectively.

We have to find the dist of two bodies with their respective travel times.

DIST OF A:

S=ut + 1/2 at²

S=0 + 1/2 (2 * 2²) => S= 4m

DIST OF B:

S=0 + 1/2 (2 * 1²) => S= 1m

SEPARATION=DIST OF A - DIST OF B

Separation = 4 - 1 => 3m..

ALTERNATIVE:

Find the final velocity of B.

v=u+ at

v=0 + 2*1 => 2m/s

Now, imagine A will travel till the end of next sec with the above mentioned velocity as its initial velocity and the dist covered will be the separation gap.

Therefore,

S=ut+ 1/2 at²

S=(2 * 1) + 1/2 (2 * 1²) => 3m..

Answer 2

Answer:

B starts 1sec later than A.

So, at the end of next sec total travel time of A & B will be 2 sec & 1 sec respectively.

We have to find the dist of two bodies with their respective travel times.

DIST OF A:

S=ut + 1/2 at²

S=0 + 1/2 (2 * 2²) => S= 4m

DIST OF B:

S=0 + 1/2 (2 * 1²) => S= 1m

SEPARATION=DIST OF A - DIST OF B

Separation = 4 - 1 => 3m..

ALTERNATIVE:

Find the final velocity of B.

v=u+ at

v=0 + 2*1 => 2m/s

Now, imagine A will travel till the end of next sec with the above mentioned velocity as its initial velocity and the dist covered will be the separation gap.

Therefore,

S=ut+ 1/2 at²

S=(2 * 1) + 1/2 (2 * 1²) => 3m..

Explanation: Pls mark me as the brainliest