Question

Two bodies are dropped from the height of h1 and h1 stimuosly. Prove that ratio of their time taken is root h1/h2

Answer 1

use second equation of motion and u=o
a=g(gravitation)

Answer 2

Explanation:u=0

                     a=g     T=$\sqrt{2H/g}$

     T1^2=2h1/g

      T2^2=2h2/g

    T1^2/T2^2=h1/h2

$\sqrt{h1/h2}$=T1/T2