Two bodies are in equilibrium who suspended in water from the arms of a balance the mass of one body is 28g and its density is 560 g/cm. If the mass of the other body is 36g what is its density?
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W1=W2W1=W2
⇒m1g−V1ρwg=m2g−V2ρwg⇒m1g−V1ρwg=m2g−V2ρwg
=m1−V1ρw=m2−V2ρw=m1−V1ρw=m2−V2ρw
=36−4×1=48−V2×1=36−4×1=48−V2×1
⇒V2=48−32=16m3⇒V2=48−32=16m3
ρ=m2V2=4816=3g/cm3
⇒m1g−V1ρwg=m2g−V2ρwg⇒m1g−V1ρwg=m2g−V2ρwg
=m1−V1ρw=m2−V2ρw=m1−V1ρw=m2−V2ρw
=36−4×1=48−V2×1=36−4×1=48−V2×1
⇒V2=48−32=16m3⇒V2=48−32=16m3
ρ=m2V2=4816=3g/cm3
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