Two bodies are projected at angles θ and (90∘−θ) with the horizontal at the same speed.The ratio of their maximum heights is
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Answer:
the ratio of their maximum height =
(
tan
θ
)
2
Explanation:
As the two bodies are being projected with velocity u
at angle
θ
and
(
90
−
θ
) respectively ,
their velocity component in vertical direction will be
u
.
sin
(
θ
)
and
u
.
sin
(
90
−
θ
)
=
u
cos
θ
respectively.
At the maximum height the final velocity (v) in vertical
direction will be zero for both bodies.
Therefore
using the relation between u, v and
the distance traversed h one can write -
v
2
=
u
2
−
2
.
g
.
h
in which v=0 ; We get
h
=
u
2
2
g
and
for first body height will be
h
1
=
(
u
.
sin
θ
)
2
2
g
and for the second body
h
2
=
(
u
cos
θ
)
) ^2
/
(
2
g
)
so
h
1
h
2
=
(
tan
Θ
)
2
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