Question

Two bodies begin a free fall from the same height at an interval of 2 second apart. How long after the first body begins its fall will the two bodies be separated by a distance of 40m​

Answer 1

Answer:

6 sec

Explanation:

let us assume that after t sec of the free fall of the first ball ,the bodies are separated by 40m.

so,the second ball has travelled for (t-2) sec.

so,

s1=1/2*g*t²

s2=1/2*g*(t-2)²

where s1 and s2 are the distance travelled by 1st and 2nd balls respectively

given:

s1-s2=40

1/2*g*{t²-(t-2)²}=40

1/2*10*(2t-4)=40

t-2=4

t=6 sec