Question

Two bodies have equal masses and moving with uniform velocity 2v and 3V what is the ratio of the kinetic energy and potential energy

Answer 1

$\huge\underline\green{\sf Answer}$

$\large{\boxed{\sf {\frac{KE}{PE}} = 4:9}}$

$\huge\underline\green{\sf Solution}$

We know that

Kinetic Energy (KE) = Potential Energy (PE)

So ,

$\large{\sf KE \alpha {v}^{2}}$

$\large{\sf {\frac{KE}{PE}}= {\frac{{V_{1}}^{2}}{{V_{2}}^{2}}}$

$\large\implies{\sf {\frac{{2v}^{2}}{{3v}^{2}}}}$

$\large\implies{\sf {\frac{4{v}^{2}}{9{v}^{2}}}}$

$\large{\boxed{\sf {\frac{KE}{PE}}={\frac{4}{9}}}}$

OR

$\large{\boxed{\sf KE:PE = 4:9}}$