Question

Two bodies have masses in ratio 3:4. When a force is applied on the first body, it moves with an acceleration of 6m/s^2. When the same force is applied on the second body, what acceleration would it produce?

Answer 1

HEY BUDDY..!!!

HERE'S THE ANSWER..


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▶️ First we'll note the data given to us

⏺️ Let those bodies having masses M1 and M2

✔️ It is given ,

♠️ M1 / M2 = 3 / 4 _________ ( 1 )


✔️ When Force is applied on M1 it accelerates with [ 6 m / s^2 ] , i.e a1

♠️ F = M1 × a 1

=> { F = M1 × 6 } __________( 2 )

▶️ Now similarly, same Force is applied on M1 and Acceleration a2 is produced which we have to find ..

♠️{ F = M2 × a2 } _________( 3 )


✔️✔️ Now dividing eqn ( 2 ) by ( 3 )

=> F / F = ( M1 × 6 ) / ( M2 × a2 )

⏺️ F will be cancelled, as it is same in both cases

=> F / F = ( M1 / M2 ) × ( 6 / a2 )

⏺️ by using eqn ( 1 )

=> F / F = 3 / 4 × 6 / a2

=> F / F = 18 / 4 a2

=> 1 = 18 / 4 a2

=> [ a2 = 18 / 4 m / s^2 ]



♠️ So the Acceleration produced is { 18 / 4 m / s^2 }



HOPE HELPED...


JAI HIND..


:-)

Answer 2

force is same

m1 : m2 = 3 : 4

F = m1 . a1

F = m1. 6------1

F = m2 . a2------2

dividing 1 by 2

a2 = 3 × 6 / 4

a2 = 18 /4