Question

Two bodies have masses in the ratio 3:4.When a force is applied on the first body,it moves with an acceleration of 12 metre per second square .How much acceleration will the same force produce in the other body?

Answer 1

Answer:

Hope you will understand

Answer 2

Solution :

⏭ Given:

✏ Ratio of masses of two bodies = 3 : 4

✏ Acceleration produced in first body = 12m$s^{-2}$

⏭ To Find:

✏ Acceleration produced in second body with the help of same force.

⏭ Concept:

✏ As per second law of newton, Relation between external force and acceleration is given by

$\star \: \underline{ \boxed{ \bold{ \sf{ \pink{ \large{F = ma}}}}}} \: \star$

⏭ Calculation :

✏ Since, external force is same for both bodies....we can write

$\implies \sf \: m_1a_1 = m_2a_2 \\ \\ \implies \sf \: \dfrac{m_1}{m_2} = \dfrac{a_2}{a_1} \\ \\ \implies \sf \: \dfrac{3}{4} = \dfrac{a_2}{12} \\ \\ \implies \sf \: a_2 = \frac{12 \times 3}{4} \\ \\ \implies \sf \: a_2 = \dfrac{36}{4} \\ \\ \implies \: \underline{ \boxed{ \bold{ \sf{ \pink{ \large{a_2 = 9 \: m {s}^{ - 2} }}}}}} \: \gray{ \bigstar}$