Question

two bodies m1 and m2 [m1 > m2] have equal kinetic energies which will have greater momentum

Answer 1

Both will have same momentum and their kinetic energies are same and equal, and kinetic energy =p^2/2m.

Answer 2

HEY MATE HERE IS YOUR ANSWER........







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the relation between mass, kinetic energy and momentum is in scalar form as momentum square is appearing in that relation:

Kinetic energy K= p^2/(2m)

K1=p1^2/(2M1)=p2^2/2M2)=K2.( Because kinetic energies are given equal.)

p1/p2=sqrt(M2/M1).

If M2>M1 ,suppose, then

p1>p2.

Now, in some answers relativity has been brought in picture. For this we have to assume velocities in relativistic region.

In that case,kinetic energy = mc^2=( cp)^2- (moc^2)^2.

For equal kinetic energy,

(cp1)^2- (M1c^2)^2 =(cp2)^2-(M2c^2)^2.

Or

(cp1)^2-(cp2)^2=(M1c^2)^2-(M2c^2)^2. So,if

M2>M1,

p2>p1.

This result differs from non relativistic result!!

Remember that the questioner has not mentioned M1 and M2 as rest masses.

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HOPE IT HELPS YOU MATE....





















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