Question

(x-y)^2a^2+2(x+y)(x+y)ab+(x+y)^2b^2

Answer 1

$\textbf{Answer :}$

Now,

(x - y)² a² + 2 (x + y) (x - y) ab
+ (x + y)² b²

= {(x - y)a}² + 2 {(x + y)a} {(x - y)b}
+ {(x + y)b}²

= {(x - y)a + (x + y)b}²,

[using the identity
p² + 2pq + q² = (p + q)²]

= (ax - ay + bx + by)²

= (ax - ay + bx + by) (ax - ay + bx + b),

which is the required factorization.

#$\textbf{MarkAsBrainliest}$