Question

two bodies of different masses are kept at a certain distance. if mass of one of the bodies is double keeping the mass of the other body fixed and if the distance between the two bodies increased by 3 times then what will happen to the force of attention aching between them

Answer 1

Answer:2/9F1

Explanation:F1=G×m1×m2/r^2

F2=G×m1×2m2/(3r)^2

F2=2/9F1

Answer 2

Let the two mass be M and m seperated by distance r.

F=GMm/r^2

A.T.Q

(new)F=G 2Mm/(3r)^2

(new)F=(GMm/r^2)*2/9

(new)F=F(old)*2/9