Question

Two bodies of equal masses 1kg are collided. After collision one of the bodies is moving with a velocity of 4ms−1 . If the total KE of system after collision is 12.5 J, then velocity of second body is

Answer 1

Explanation:

Using momentum conservation

m

1

×2−4m

2

=(m

1

+m

2

)

⇒m

1

=5m

2

Ratio of K.E=

2

1

×m

2

×(4)

2

2

1

×m

1

×(2)

2

=

m

2

×16

5m

2

×4

=1.25