Question

Two bodies of equal masses move with uniform velocity v and 3v respectively.
Find the ratio of kinetic energies​

Answer 1

Answer:

Explanation:

Let the mass me m

$v_{1}=v\\v_{2}=3v\\ \\K.E_{1} =\frac{1}{2} mv^{2} \\K.E_{2}=\frac{1`}{2}m(3v)^{2}  \\\frac{K.E_1}{K.E_2}=\frac{\frac{1}{2}mv^2 }{\frac{1}{2}9mv^2 }  \\\frac{K.E_1}{K.E_2}=\frac{1}{9}$

Answer 2

Answer:1:3

Explanation:

Required ratio=1/2mv2÷3/2mv2