two bodies of equal masses move with uniform velocity v and 3V respectively find the ratio of their kinetic energies
Answers
Answered by
1
K.E= 1/2 mv^2
Therefore
K/K'= 1^2/3^2= 1:9
Answered by
4
Here is your answer!!!!
KE is proportional to (velocity)^2
KE1: KE2 =( v)^2:(3v)^2
KE1:KE2 = 1:9
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