Two bodies of equal weight are kept
at heights of h and 1.5h respectively.
The ratio of their potential energy is
Answers
Answered by
16
Answer:
P.E=mgh
m and g constant so p.e is directly proportional to h
p.e at body 1 =h
p.e at of body 2=1.5h
ratio=P.E of body 1/P.E of body 2
so
body1/bod2=h/1.5h
body1/body2=10/15=2/3
ratio P.E of body 1 by body to is 2:3
and
PE of body 2 by body 1=3:2
Explanation:
P.E=potential anergy
Answered by
2
Answer:
2:3 because kinetic energy +potential energy
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