Question

two bodies of mass 1kg and 4kg have equal kinetic energy.wat is the ratio of their momentum?

Answer 1

kinetic energy is given by:
$e = \frac{1}{2} \times m \times {v}^{2}$
so taking velocity for mass 1kg as v1, we get
$e1 = \frac{1}{2} \times (1) \times {v1}^{2}$
and taking velocity for mass 4kg as v1, we have
$e2 = \frac{1}{2} \times (4) \times {v2}^{2}$
given that e1 = e2, so
equating the above terms and simplifying, we get
$\frac{ {v1}^{2} }{ {v2}^{2} } = 4$
or
$| \frac{v1}{v2} | = 2$
now , momentum is given by
$p = m \times v$
let us assume , p1 as momentum for mass 1kg and p2 for mass 4kg
so
p1 = 1 × v1
and p2 = 4×v2

and
$\frac{p1}{p2} = ( \frac{1}{4} ) \times ( \frac{v1}{v2} )$
so we have
$| \frac{p1}{p2} | = \frac{1}{2}$

Answer 2

Answer:

this is your required answer..........