two bodies of mass 2g and 3g has position vectors 3i+2j+1k,i-j+3k respectively.find distance of center of mass from the origin
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Position Vector r of centre of mass of two bodies of mass m1 and m2 with position vector r1 and r2 is given by
r = (m1 r1 + m2 r2)/( m1+m2 )
r= ( 6i+4j+2k + 3i-3j+9k)/(2+3)
r= (9i+j+11k) /5
distance from origin is magnitude of this vector
1/5 √(81+1+121)
1/5 √(203)
that's your answer
r = (m1 r1 + m2 r2)/( m1+m2 )
r= ( 6i+4j+2k + 3i-3j+9k)/(2+3)
r= (9i+j+11k) /5
distance from origin is magnitude of this vector
1/5 √(81+1+121)
1/5 √(203)
that's your answer
b394184:
it's a little weird answer let me check the calculation again
okay now looks good
thanx bro
no prob
A rod is of length 'L' and its mass acting per unit length is directly proportional to distance 'S' from its end.find distance of centre of mass for that end of the rod
please tell this also
wait I have to take a bath :P
i will don't worry
okk
are you in 11th?
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