two bodies of masses 1 kg and 2 kg are attached to the ends of 2m long weightless rod . this system is rotating about an axis passing through the middle point of rod and perpendicular to length. calculate M.I of system
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this system is rotating about an axis passing through the middle point of rod and perpendicular to length. calculate m.l of system .
Answered by
1
Answer:
3kg-m^2
Explanation:
TotalMI=MI of 2 body passing from axis+MI of rod passing through axis
=M1r^2+M2r^2+Mr^2/12
1×1+2×1+0 since rod is massles
=3kg-m^2
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