Question

Two bodies of masses 10 kg and 15 kg are kept at a distance of 500 cm apart.Find the amount of force acting between them.

Answer 1

Two bodies of masses 10 kg and 15 kg are kept at a distance of 500 cm apart.

so, mass of first body , m = 10 kg
mass of 2nd body , M = 15 kg
separation between m and M , r = 500cm = 5m

use Gravitational force formula,
F = GMm/r² , where G is gravitational constant and G = 6.67 × 10^-11 Nm²/kg²

so, F = 6.67 × 10^-11 × 10 × 15/(5)²
= 6.67 × 150 × 10^-11/25
= 6.67 × 6 × 10^-11
= 4.002 × 10^-10 N

hence, force between them is 4.002 × 10^-10N

Answer 2

According to given information, we have

m1 = 10 kg

m2 = 15 kg

distance = d = 500 cm = 500/100 = 5 m

According to law of attraction, the force of attraction between two bodies is

⇒ directly proportional to their &

⇒ inversely proportional to the square of distance between them

So we have

F = (Gm1m2)/(d^2)

F  = (6.674×10^-11×10×15)/(5^2)

F = 40× 10 ^-11

F = 4 × 10^-10 Newton

So the force acting between them is   F  =  4 × 10^-10 Newton