Question

Two bodies of masses 10 kg and 40 kg are tied to the ends of a light string and kept on a smooth horizontal surface. A horizontal force F = 500 N is applied to 10 kg along the direction of string. What is the tension in the string?

Answer 1

Mass of body 1 = 10 kg

Mass of body 2 = 40 kg

As the surface is smooth , so there will be no friction .

Horizontal force applied on 10 kg block = 500 N

Let us calculate the net acceleration of the system ,

➠ F = ( 10 + 40 ) a

➠ a = 500/50

➠ a = 10 m/s²  $\pink{\bigstar}$

Find attachment for entire scenario .

Apply FBD for 10 kg block ,

➙ 500 - T = (10)(10)

➙ T = 500 - 100

➙ T = 400 N  $\orange{\bigstar}$

Tension in the string = 400 N

Answer 2

Answer:

Question

Two bodies of masses 10 kg and 40 kg are tied to the ends of a light string and kept on a smooth horizontal surface. A horizontal force F = 500 N is applied to 10 kg along the direction of string. What is the tension in the string?

To find

the tension in the string

Solution

Mass of body 1 = 10kg

Mass of body 2 = 40 kg

Surface type - Smooth

➡️ Horizontal force applied on 10 kg block = 500 Newton

We have to calculate the net acceleration of the system

Formula applied -

F = ( Mass of body 1 + Mass of body 2) a

F = (10 +40) a

A =500/50

A = 10 m/s

Apply FBD for 10 kg block ,

➡️500 - T = (10)(10)

➡️T = 500 - 100

➡️T = 400 N

Thus , the tension in the string = 400 Newton

$\huge \fbox {Hope it helps}$