Question

Two bodies of masses 6kg and 4kg are along eastern and northern directions with velocities 5m/s^-1 and 10m/s^-1 respectively . Find the magnitude of velocity of centre of mass​

Answer 1

Explanation:

Let east direction be x axis and north be y axis. Then, velocity of first body is v

1

=5im/s and that of body 2 will be v

2

=3jm/s. Since velocity of center of mass is given by

v

cm

=

m

1

+m

2

m

1

v

1

+m

2

v

2

=

4+5

4(5i)+5(3j)

=

9

20

i+

9

15

jm/s

Hence, magnitude of velocity is ∣v

cm

∣=

9

400+225

m/s=

9

25

m/s.