Question

Two bodies of masses m1 and m2 have equal kinetic energies. What is the ratio of their linear momemta?

Answer 1

1/2m1v1^2=1/2m2v2^2 (as given in question) m1v1v1=m2v2v2 (m1v1 is the momentum of body 1 & m2v2 is the momentum of second body)
P1v1=p2v2
P1/p2=v2/v1
That is your answer

Answer 2

Hey there!

Given,

Two bodies m1 and m2

Let the velocity of 1st body be = v1

Then its Kinetic energy = p²/2m1=(m1v1)²/2m2

Let the velocity of 2nd body be = v2

Then its Kinetic energy = p²/2m2 = (m2v2)²/2m2

Now, (m1v1)²/2m1 = (m2v2)²/2m2

 ∴(m1v1)/(m2v2) = $\frac{ \sqrt{2m2} }{ \sqrt{2m1} }$

Then Ratio = √(2m2) : √(2m1)

Hope It Helps You!