Question

Two bodies of masses m1 and m2 have equal kinetic energy. If p1 and p2 are their respective momentum , then ratio of p1 : p2 is ......?
help me mates...❤

Answer 1

⭐⭐⭐⭐⭐ ANSWER ⭐⭐⭐⭐⭐

✔ Given, two bodies m1 and m2

✔ Let us consider the velocity of 1st body be = v1

✔ Then its Kinetic energy = p²/2m1=(m1v1)²/2m2

✔ Let us consider the velocity of 2nd body be = v2

✔ Then its Kinetic energy = p²/2m2 = (m2v2)²/2m2

✔ Now, (m1v1)²/2m1 = (m2v2)²/2m2

 ∴ (m1v1)/(m2v2) = √2m2/√2m1

✔ Therefore, ratio = √2m2 : √2m1 (Ans.)

⭐⭐⭐ ALWAYS BE BRAINLY ⭐⭐⭐⭐

Answer 2

Hey there!

Given,

Two bodies m1 and m2

Let the velocity of 1st body be = v1

Then its Kinetic energy = p²/2m1=(m1v1)²/2m2

Let the velocity of 2nd body be = v2

Then its Kinetic energy = p²/2m2 = (m2v2)²/2m2

Now, (m1v1)²/2m1 = (m2v2)²/2m2

 ∴(m1v1)/(m2v2) = $\frac{ \sqrt{2m2} }{ \sqrt{2m1} }$

Then Ratio = √(2m2) : √(2m1)

Hope It Helps You!