Question

Calculate ph of 4*10^-3 m y(oh)2 solution assuming first step dissociate to be 100 and second step 50

Answer 1

When looking at this problem, all you need to know is the tricks the examiners are currently using. So as a student you need to be equipped with various approaches to questions given.

In this case, the steps of dissociation are given as 100 and then finally to 50. What it means is that this dissociation is reducing by half and hence the degree of dissociation is 0.5.

But the equillibrium concentration is as follows;

[OH-] is 8 x 10^-3

then its equilibrium concentration is C∝ where ∝ is the degree of dissociation

[OH-] = (8x 10^-3) x 0.5

         = 4 x 10^-3 moles

Hence pOH= -log 4 x 10^-3

                    = 2.4

Thus pH= 14 - 2.4

          pH= 11.6

Answer 2

Explanation:

ph =11.6.pls marke brainliest answer