Two bodies of same mass start from rest and move with velocity v and 2v respectively. Find the ratio of the kinetic energy
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ke1=1/2mv^2
ke2=1/2m4v^2
dividing ke1 by ke2
ke1/ke2=1/4
1:4 is the answer
ke2=1/2m4v^2
dividing ke1 by ke2
ke1/ke2=1/4
1:4 is the answer
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