Two boys are on either side of their school building of 20 m height observe its top at the angles of elevation 30 and 60 respectively. Find the distance between the two boys.
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Answer:
Step-by-step explanation:
P=20
Angle A=30
B1= ?
Tan30=P/B
1/√3=20/B1
B1=20√3m
B2=?
Angle B = 60
Tan60=P/B
√3=20/B2
B2=20/√3
B2=20√3/√3 m.
Distance between two boys=B1+B2
=20√3+20√3/3
=60√3/3+20√3/3
=80√3/3m.
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