Question

two boys are standing on opposite sides of Tower of height 70 meters observed that the angle of elevation of the top of the tower is 30° to 45° respectively. find the distance between teo boys​

Answer 1

Answer:

You can see the answer in adjoining pic.

Hope it helps...

Answer 2

Answer:

70(√3+1) meters

Step-by-step explanation:

In the given figure,

AC = Tower of height 70m

To find: Distance between the boys = BD = BC + CD

In triangle ACB

tan B = AC/BC

tan 30° = 70/BC

1/√3 = 70/BC (tan 30° = 1/√3)

BC = 70√3 meters

In triangle ACD

tan D = AC/CD

tan 45° = 70/CD

1 = 70/CD (tan 45° = 1)

CD = 70 meters

Therefore,

Distance between the boys = BD = BC + CD

= 70√3 + 70

= 70(√3 + 1) meters