Question

Two brass balls of masses 2 kg and 0.5 kg experience a force of attraction of 2N. What is the force of attraction when the distance between their centers is doubled?

Answer 1

Answer:

force between the balls= 2N

g=GmM/r²

g'=GmM/(2r)²=GmM/4r²

by equating g and g'

GmM/r²=GmM/4r²

so g=g'/4 or 4g=g'

if u got confused then in the equation just cancel out GmM/r² and u get the ratio 1:1/4

as g' is the new value of g after doubling distances, so let's substitute 2N with g as it is its value if distance is not doubled.

so 2N=4g'

g'=1/2 N

hope this helped

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