two buildings are constructed with a uniform width pathway around and in between the buildings as shown in the figure find the width of the pathway also find the area of the pathway
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Let Width of pathway be 'x'
x + x + x +25 +25 = 65
3x +50 = 65
3x = 65 - 50
x = 15
x = 15/3
x = 5 Ft.
Width of Pathway = 5 Ft.
Area of 2 buildings and with pathway = L*B
= 65*35
= 2275 Ft sq
Area of 1 building = Side*Side
= 25 * 25
= 625 Ft sq
Area of 2 buildings = 625*2
= 1250 Ft sq
Area of Pathway = Area of 2 Buildings with Pathway - Area of 2 buildings
= 2275 - 1250
= 1025 Ft sq
If you are satisfied. Please mark my answer as the brainliest.
x + x + x +25 +25 = 65
3x +50 = 65
3x = 65 - 50
x = 15
x = 15/3
x = 5 Ft.
Width of Pathway = 5 Ft.
Area of 2 buildings and with pathway = L*B
= 65*35
= 2275 Ft sq
Area of 1 building = Side*Side
= 25 * 25
= 625 Ft sq
Area of 2 buildings = 625*2
= 1250 Ft sq
Area of Pathway = Area of 2 Buildings with Pathway - Area of 2 buildings
= 2275 - 1250
= 1025 Ft sq
If you are satisfied. Please mark my answer as the brainliest.
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