Math, asked by StarTbia, 1 year ago

Two buildings are in front of each other on a road of width 15 meters. From the top of the first building, having a height of 12 meter, the angle of elevation of the top of the second building is 30°.What is the height of the second building?

Answers

Answered by Anonymous
131
\textbf{Given that ,}

□ Two buildings are in font of each other on a road of width ( base ) = 15 m.

□ Height of the first building ( perpendicular ) = 12 m

□ And the angle of elevation of the top of the second building from first building = 30°.

□ Height of the second building = ?

□ Let's solve this question ,
______________________________________________________________

□ Let's suppose the height of the another remaining building be " x "

□ Then height of second building = " x " + height of first building.

□ Height of second building = x + 12.

□ Base of the building = base at the top of building.

=> 15 = 15

According to the question ,

=> Tan30° = perpendicular / base

[ Value of Tan30° = 1 / √3 ]

=> 1 / √3 = x / 15

=> x√3 = 15

=> x = 15 / √3

□ Now , we have to multiply 15 /√3 by √3 / √3

=> x = ( 15 /√3 ) × (√3 / √3 )

=> x = ( 15√3 ) / 3

=> x = 5√3

Hence , height of the remaining building = 5√3

[ Value of √3 = 1.73 ]

Now ,

=> 5 × 1.73

=> 8.65

□ Now , total height of the building = x + height of the first building [ as both are parallel ].

=> 8.65 + 15 = 23.65

□ Hence , the total height of the another building is 23.65 m. or 5√3 + 12.



\textbf{Thanks !!}

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Answered by ajjubhai9429
10

Answer:

Two buildings are in front of each other on a road of width 15 meters. From the top of the first building, having a height of 12 meter, the angle of elevation of the top of the second building is 30°.What is the height of the second building?

Answer:

Let AB and CD be two building, with

AB = 12 m

And angle of elevation from top of AB to top of CD = ∠CAP = 30°

Width of road = BD = 15 m

Clearly, ABDP is a rectangle

With

AB = PD = 12 m

BD = AP = 15 m

And APC is a right-angled triangle, In ∆APC

⇒ CP = 5√3 m

Also,

CD = CP + PD = (5√3 + 12) m

Hence, height of other building is (12 + 5√3 m).

Step-by-step explanation:

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