Two bulbs have filament of length emissivities and diameter in the ratio 2:1.if ratio of their power is 1:2 the ratio of their temperature is
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Answer:
We know that emission from the surface is given by following relation:
E=εσAT
4
E
2
E
1
=
ε
2
A
2
T
2
4
ε
1
A
1
T
1
4
E
2
E
1
=
4ε×d×2L×3
4
3ε×2d×L×2
4
=
27
4
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